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19683
Posts: 151
Joined: Wed Jun 05, 2013 12:15 pm

Re: Welcome!

Post by 19683 »

Hi, I'm 19683. I've been addicted to velocity raptor for a while...

I just registered, and it's nice to have a forum!
Binomial Theorem: ((a+b)^n)= sum k=0->k=n((n!(a^(n-k))(b^k))/(k!(n-k)!))
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robly18
Posts: 413
Joined: Tue Jun 04, 2013 2:03 pm

Re: Welcome!

Post by robly18 »

Hi. I agree, this way I don't have to fill Andy's inbox full of e-mails!
Convincing people that 0.9999... = 1 since 2012
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testtubegames
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Joined: Mon Nov 19, 2012 7:54 pm

Re: Welcome!

Post by testtubegames »

19683 wrote:Hi, I'm 19683.
Welcome! (Thanks to google) I know it's some large power of three. I sense there's a story behind that login?
robly18 wrote:Hi. I agree, this way I don't have to fill Andy's inbox full of e-mails!
A real time saver for me! ;) Then again, I imagine the forum might be its own time-sink... If I'm on here too much, chastise me and tell me to go make some games, okay?
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robly18
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Joined: Tue Jun 04, 2013 2:03 pm

Re: Welcome!

Post by robly18 »

testtubegames wrote:If I'm on here too much, chastise me and tell me to go make some games, okay?
Don't say that. Trust me.

If we could, we'd make ten clones of you and put you all working on games. And maybe take one of you to lecture us about science stuff.
Convincing people that 0.9999... = 1 since 2012
19683
Posts: 151
Joined: Wed Jun 05, 2013 12:15 pm

Re: Welcome!

Post by 19683 »

testtubegames wrote:
19683 wrote:Hi, I'm 19683.
Welcome! (Thanks to google) I know it's some large power of three. I sense there's a story behind that login?
robly18 wrote:Hi. I agree, this way I don't have to fill Andy's inbox full of e-mails!
A real time saver for me! ;) Then again, I imagine the forum might be its own time-sink... If I'm on here too much, chastise me and tell me to go make some games, okay?
Yes, there is a story. I was reading about tetration, and I wanted to calculate 3 tetrated by 3. I should have calculated 3^27=7625597485*(10^3), but i made a mistake and calculated 3^9=19683.

7625597485*(10^3) was too long to memorise, so 19683 became my favorite number.
Binomial Theorem: ((a+b)^n)= sum k=0->k=n((n!(a^(n-k))(b^k))/(k!(n-k)!))
19683
Posts: 151
Joined: Wed Jun 05, 2013 12:15 pm

Re: Welcome!

Post by 19683 »

robly18 wrote:
testtubegames wrote:If I'm on here too much, chastise me and tell me to go make some games, okay?
Don't say that. Trust me.

If we could, we'd make ten clones of you and put you all working on games. And maybe take one of you to lecture us about science stuff.
If I could, I would colonize the universe with trillions of clones of you making awesome games.

Quick Question: About when will shoctopus be released? I'm thinking about playtesting...
Binomial Theorem: ((a+b)^n)= sum k=0->k=n((n!(a^(n-k))(b^k))/(k!(n-k)!))
A Random Player
Posts: 523
Joined: Mon Jun 03, 2013 4:54 pm

Re: Welcome!

Post by A Random Player »

19683 wrote:
testtubegames wrote:
19683 wrote:Hi, I'm 19683.
Welcome! (Thanks to google) I know it's some large power of three. I sense there's a story behind that login?
robly18 wrote:Hi. I agree, this way I don't have to fill Andy's inbox full of e-mails!
A real time saver for me! ;) Then again, I imagine the forum might be its own time-sink... If I'm on here too much, chastise me and tell me to go make some games, okay?
Yes, there is a story. I was reading about tetration, and I wanted to calculate 3 tetrated by 3. I should have calculated 3^27=7625597485*(10^3), but i made a mistake and calculated 3^9=19683.

7625597485*(10^3) was too long to memorise, so 19683 became my favorite number.
Heh, when I saw your username, I actually recognized that the number had some meaning, but didn't remember what. Then I put it into wolfram alpha, which immediately gave me 3^9, and realized I should have known that.
$1 = 100¢ = (10¢)^2 = ($0.10)^2 = $0.01 = 1¢ [1]
Always check your units or you will have no money!
19683
Posts: 151
Joined: Wed Jun 05, 2013 12:15 pm

Re: Welcome!

Post by 19683 »

A Random Player wrote:Heh, when I saw your username, I actually recognized that the number had some meaning, but didn't remember what. Then I put it into wolfram alpha, which immediately gave me 3^9, and realized I should have known that.
I love wolfram alpha.

I made a cool shape by entering (x^4)+(y^4)=1
Binomial Theorem: ((a+b)^n)= sum k=0->k=n((n!(a^(n-k))(b^k))/(k!(n-k)!))
19683
Posts: 151
Joined: Wed Jun 05, 2013 12:15 pm

Re: Welcome!

Post by 19683 »

Which code is used to program these games?

C++?
Binomial Theorem: ((a+b)^n)= sum k=0->k=n((n!(a^(n-k))(b^k))/(k!(n-k)!))
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testtubegames
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Joined: Mon Nov 19, 2012 7:54 pm

Re: Welcome!

Post by testtubegames »

The flash games are written using ActionScript (AS3). The iOS games are written in Objective-C.
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